How to get rid of ln in chemistry

In the simplest case, the logarithm of an unknown number equals another number:

\(\log x = y\)

Raise both sides to exponents of 10, and you get

\(10^ {\log x} = 10^y\)

Since 10^{(log x)} is simply x, the equation becomes

\(x = 10^y\)

When all the terms in the equation are logarithms, raising both sides to an exponent produces a standard algebraic expression.

For example, raise

\(\log (x^2 – 1) = \log (x + 1)\)

to a power of 10 and you get:

\(x^2 – 1 = x + 1\)

which simplifies to

\(x^2 – x – 2 = 0.\)

The solutions are x = −2; x = 1.

In equations that contain a mixture of logarithms and other algebraic terms, it's important to collect all the logarithms on one side of the equation.

You can then add or subtract terms. According to the law of logarithms, the following is true:

\(\log x + \log y = \log(xy) \
\,\
\log x – \log y = \log \bigg(\frac{x}{y}\bigg)\)

Here's a procedure for solving an equation with mixed terms:

Start with the equation: For example

\(\log x = \log (x – 2) + 3\)

Rearrange the terms:

\(\log

how do you cancel out ln in an equation

how do you cancel ln